mohon yah kak bantuan nya
80°C
Penjelasan:
m = 400 g = 0,4 Kg
Q = 9.360 J
c = 390 J/kg.°C
suhu awal = 20°C
Q = m x c x ∆t
∆t = Q : (m x c)
= 9.360 : (0,4 x 390)
= 9.360 : 156
= 60°C
∆t = suhu akhir - suhu awal
suhu akhir = suhu awal + ∆t
= 20°C + 60° C
= 80°C
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